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When you have a sequence of characters, they are piled next to each other in memory, and the location of the first character in that. If i create a pointe. Similarly, char** is a pointer to a char*.
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Is a pointer to the literal (const) string test. The array owns its contents,. The compiler should complain, because you're constructing an array of char arrays (or char pointers), and assigning it to an array of chars.
287 char* and char[] are different types, but it's not immediately apparent in all cases.
Technically, the char* is not an array, but a pointer to a char. The first question is at this point. First of all i create a p pointer, which points to a char. Making it a pointer to a pointer to a char.
I would like to understand how pointers work, so i created this small program. // assign the address of the string literal 1234556 to str as @oli charlesworth commented, if you use a pointer to a constant. The char type can only represent a single character. The variables with the * are pointers.
// allocate a space for char pointer on the stack str = 1234556;
So what is the difference? I want to know what actually happens in terms of storage duration, both at compile and run time. This is because arrays decay into pointers, meaning that if an expression of type char[] is provided. I've read so many threads and questions about it and read so many answers but still having difficulties understanding the differences and when you should use what ?
The main difference between them is that the first is an array and the other one is a pointer. Those types don't match up.
